Old Skool Maths

[Xp197777]

Has anyone got the correct answer yet I’m still with 15

[jpayne]

well I truly believe I have it right at 15!
the laws of Mathematics dictate I am correct.

JP

[Xp197777]

I agree jp

[voodoo57]

Surely it's 70? if a piston is 10  a tyre is 5 and a shock is 2 or am i still very bad at geography?

[Monza]

A pair of shocks are 2.....there's only 1 shock in the sum....I'm not too good at history tbh

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[Vista]

There's been a few correct answers and some key rings gone out. 

[voodoo57]

10 hours ago, GT65 said:

A pair of shocks are 2.....there's only 1 shock in the sum....I'm not too good at history tbh

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You bastard! I was chuckiling so much my jaw started to ache!

[jpayne]

Its been long enough. Thanks for the keyring Vista.

3 pistons = 30 hence a piston equals 10

a piston plus a tyre plus a tyre = 20 a piston already = 10 so tyres must equal 5

a tyre plus a pair of shock absorber plus a pair of shock absorber = 9 thus a pair of shock absorbers must = 2

Our final equation poses a tyre + a single shock absorber X a piston or 5+1x10.

Mathematics does not have a primary left to right protocol but an order of operations or rules. Some know it as BODMAS, others BIDMAS or PEDMAS.

SO when presented with an equation solve the Bracketed then Orders, Divisions, Mutiplications, then Additions and finally Subtractions. so following the RULE our equation would look like this when reordered to read left to right. 1x10+5 or 5+(1x10) or as presented 5+1x10 which equals 15

 

JP

[Monza]

Fair enough......

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[Vista]

1 hour ago, jpayne said:

Its been long enough. Thanks for the keyring Vista.

3 pistons = 30 hence a piston equals 10

a piston plus a tyre plus a tyre = 20 a piston already = 10 so tyres must equal 5

a tyre plus a pair of shock absorber plus a pair of shock absorber = 9 thus a pair of shock absorbers must = 2

Our final equation poses a tyre + a single shock absorber X a piston or 5+1x10.

Mathematics does not have a primary left to right protocol but an order of operations or rules. Some know it as BODMAS, others BIDMAS or PEDMAS.

SO when presented with an equation solve the Bracketed then Orders, Divisions, Mutiplications, then Additions and finally Subtractions. so following the RULE our equation would look like this when reordered to read left to right. 1x10+5 or 5+(1x10) or as presented 5+1x10 which equals 15

 

JP

Indeed. Well done all who made it 15. 

[Xp197777]

Yippee 

[Huge]

15

[katana]

10 hours ago, Huge said:

15

LOL's with the answers given, you've come up with correct one as well ! - just two years too late LOL!

[Xp197777]

Ha😆

[Huge]

I know you shouldn’t laff at your own jokes but I nearly wet myself guess a key ring’s out of the question! 😂😂😂